(2n/3)+(n/2)^3=49/6

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Solution for (2n/3)+(n/2)^3=49/6 equation: 



(2n/3)+(n/2)^3=49/6

We move all terms to the left:

(2n/3)+(n/2)^3-(49/6)=0

We add all the numbers together, and all the variables

(+2n/3)+(+n/2)^3-(+49/6)=0

We get rid of parentheses

2n/3+(+n/2)^3-49/6=0

We calculate fractions


24n^2/()+((+n*3*6)/()+()/()=0



We calculate terms in parentheses: +((+n*3*6)/()+()/(), so:

(+n*3*6)/()+()/(

We add all the numbers together, and all the variables

(+n*3*6)/()+1

We multiply all the terms by the denominator


(+n*3*6)+1*()

We add all the numbers together, and all the variables

(+n*3*6)

We get rid of parentheses

n*3*6

Wy multiply elements

18n*6

Wy multiply elements

108n

Back to the equation:

+(108n)



We multiply all the terms by the denominator


24n^2+108n*()=0

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